Optimal. Leaf size=525 \[ -\frac {1}{4} \sqrt [3]{c-\sqrt {-d^2}} x-\frac {1}{4} \sqrt [3]{c+\sqrt {-d^2}} x-\frac {\sqrt {3} \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \text {ArcTan}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c-\sqrt {-d^2}}}}{\sqrt {3}}\right )}{2 d f}+\frac {\sqrt {3} \sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \text {ArcTan}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c+\sqrt {-d^2}}}}{\sqrt {3}}\right )}{2 d f}+\frac {\sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}-\frac {\sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}+\frac {3 \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log \left (\sqrt [3]{c-\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}-\frac {3 \sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \log \left (\sqrt [3]{c+\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}+\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f} \]
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Rubi [A]
time = 0.62, antiderivative size = 525, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 10, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.435, Rules used = {3647, 3728,
3712, 3566, 726, 52, 59, 631, 210, 31} \begin {gather*} -\frac {\sqrt {3} \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \text {ArcTan}\left (\frac {\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c-\sqrt {-d^2}}}+1}{\sqrt {3}}\right )}{2 d f}+\frac {\sqrt {3} \sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \text {ArcTan}\left (\frac {\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c+\sqrt {-d^2}}}+1}{\sqrt {3}}\right )}{2 d f}+\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log \left (\sqrt [3]{c-\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}-\frac {3 \sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \log \left (\sqrt [3]{c+\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}+\frac {\sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}-\frac {\sqrt {-d^2} \sqrt [3]{c+\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}-\frac {1}{4} x \sqrt [3]{c-\sqrt {-d^2}}-\frac {1}{4} x \sqrt [3]{c+\sqrt {-d^2}}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f} \end {gather*}
Antiderivative was successfully verified.
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Rule 31
Rule 52
Rule 59
Rule 210
Rule 631
Rule 726
Rule 3566
Rule 3647
Rule 3712
Rule 3728
Rubi steps
\begin {align*} \int \tan ^4(e+f x) \sqrt [3]{c+d \tan (e+f x)} \, dx &=\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\frac {3 \int \tan (e+f x) \sqrt [3]{c+d \tan (e+f x)} \left (-2 c-\frac {10}{3} d \tan (e+f x)-2 c \tan ^2(e+f x)\right ) \, dx}{10 d}\\ &=-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\frac {9 \int \sqrt [3]{c+d \tan (e+f x)} \left (2 c^2+\frac {2}{9} \left (9 c^2-35 d^2\right ) \tan ^2(e+f x)\right ) \, dx}{70 d^2}\\ &=\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\int \sqrt [3]{c+d \tan (e+f x)} \, dx\\ &=\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\frac {d \text {Subst}\left (\int \frac {\sqrt [3]{c+x}}{d^2+x^2} \, dx,x,d \tan (e+f x)\right )}{f}\\ &=\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\frac {d \text {Subst}\left (\int \left (\frac {\sqrt {-d^2} \sqrt [3]{c+x}}{2 d^2 \left (\sqrt {-d^2}-x\right )}+\frac {\sqrt {-d^2} \sqrt [3]{c+x}}{2 d^2 \left (\sqrt {-d^2}+x\right )}\right ) \, dx,x,d \tan (e+f x)\right )}{f}\\ &=\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}-\frac {d \text {Subst}\left (\int \frac {\sqrt [3]{c+x}}{\sqrt {-d^2}-x} \, dx,x,d \tan (e+f x)\right )}{2 \sqrt {-d^2} f}-\frac {d \text {Subst}\left (\int \frac {\sqrt [3]{c+x}}{\sqrt {-d^2}+x} \, dx,x,d \tan (e+f x)\right )}{2 \sqrt {-d^2} f}\\ &=\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}-\frac {\left (d \left (c+\sqrt {-d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{\left (\sqrt {-d^2}-x\right ) (c+x)^{2/3}} \, dx,x,d \tan (e+f x)\right )}{2 \sqrt {-d^2} f}+\frac {\left (d^2+c \sqrt {-d^2}\right ) \text {Subst}\left (\int \frac {1}{(c+x)^{2/3} \left (\sqrt {-d^2}+x\right )} \, dx,x,d \tan (e+f x)\right )}{2 d f}\\ &=-\frac {1}{4} \sqrt [3]{c-\sqrt {-d^2}} x-\frac {1}{4} \sqrt [3]{c+\sqrt {-d^2}} x+\frac {\sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}+\frac {d \sqrt [3]{c+\sqrt {-d^2}} \log (\cos (e+f x))}{4 \sqrt {-d^2} f}+\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}-\frac {\left (3 d \sqrt [3]{c+\sqrt {-d^2}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{c+\sqrt {-d^2}}-x} \, dx,x,\sqrt [3]{c+d \tan (e+f x)}\right )}{4 \sqrt {-d^2} f}-\frac {\left (3 d \left (c+\sqrt {-d^2}\right )^{2/3}\right ) \text {Subst}\left (\int \frac {1}{\left (c+\sqrt {-d^2}\right )^{2/3}+\sqrt [3]{c+\sqrt {-d^2}} x+x^2} \, dx,x,\sqrt [3]{c+d \tan (e+f x)}\right )}{4 \sqrt {-d^2} f}-\frac {\left (3 \left (d^2+c \sqrt {-d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt [3]{c-\sqrt {-d^2}}-x} \, dx,x,\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d \left (c-\sqrt {-d^2}\right )^{2/3} f}-\frac {\left (3 \left (d^2+c \sqrt {-d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{\left (c-\sqrt {-d^2}\right )^{2/3}+\sqrt [3]{c-\sqrt {-d^2}} x+x^2} \, dx,x,\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d \sqrt [3]{c-\sqrt {-d^2}} f}\\ &=-\frac {1}{4} \sqrt [3]{c-\sqrt {-d^2}} x-\frac {1}{4} \sqrt [3]{c+\sqrt {-d^2}} x+\frac {\sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}+\frac {d \sqrt [3]{c+\sqrt {-d^2}} \log (\cos (e+f x))}{4 \sqrt {-d^2} f}+\frac {3 \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log \left (\sqrt [3]{c-\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}+\frac {3 d \sqrt [3]{c+\sqrt {-d^2}} \log \left (\sqrt [3]{c+\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 \sqrt {-d^2} f}+\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}+\frac {\left (3 d \sqrt [3]{c+\sqrt {-d^2}}\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c+\sqrt {-d^2}}}\right )}{2 \sqrt {-d^2} f}+\frac {\left (3 \left (d^2+c \sqrt {-d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c-\sqrt {-d^2}}}\right )}{2 d \left (c-\sqrt {-d^2}\right )^{2/3} f}\\ &=-\frac {1}{4} \sqrt [3]{c-\sqrt {-d^2}} x-\frac {1}{4} \sqrt [3]{c+\sqrt {-d^2}} x-\frac {\sqrt {3} \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c-\sqrt {-d^2}}}}{\sqrt {3}}\right )}{2 d f}-\frac {\sqrt {3} d \sqrt [3]{c+\sqrt {-d^2}} \tan ^{-1}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c+\sqrt {-d^2}}}}{\sqrt {3}}\right )}{2 \sqrt {-d^2} f}+\frac {\sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log (\cos (e+f x))}{4 d f}+\frac {d \sqrt [3]{c+\sqrt {-d^2}} \log (\cos (e+f x))}{4 \sqrt {-d^2} f}+\frac {3 \sqrt {-d^2} \sqrt [3]{c-\sqrt {-d^2}} \log \left (\sqrt [3]{c-\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 d f}+\frac {3 d \sqrt [3]{c+\sqrt {-d^2}} \log \left (\sqrt [3]{c+\sqrt {-d^2}}-\sqrt [3]{c+d \tan (e+f x)}\right )}{4 \sqrt {-d^2} f}+\frac {3 \left (9 c^2-35 d^2\right ) (c+d \tan (e+f x))^{4/3}}{140 d^3 f}-\frac {9 c \tan (e+f x) (c+d \tan (e+f x))^{4/3}}{35 d^2 f}+\frac {3 \tan ^2(e+f x) (c+d \tan (e+f x))^{4/3}}{10 d f}\\ \end {align*}
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Mathematica [C] Result contains complex when optimal does not.
time = 16.15, size = 371, normalized size = 0.71 \begin {gather*} \frac {-i \sqrt [3]{c-i d} \left (2 \sqrt {3} \text {ArcTan}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c-i d}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{c-i d}-\sqrt [3]{c+d \tan (e+f x)}\right )+\log \left ((c-i d)^{2/3}+\sqrt [3]{c-i d} \sqrt [3]{c+d \tan (e+f x)}+(c+d \tan (e+f x))^{2/3}\right )\right )+i \sqrt [3]{c+i d} \left (2 \sqrt {3} \text {ArcTan}\left (\frac {1+\frac {2 \sqrt [3]{c+d \tan (e+f x)}}{\sqrt [3]{c+i d}}}{\sqrt {3}}\right )-2 \log \left (\sqrt [3]{c+i d}-\sqrt [3]{c+d \tan (e+f x)}\right )+\log \left ((c+i d)^{2/3}+\sqrt [3]{c+i d} \sqrt [3]{c+d \tan (e+f x)}+(c+d \tan (e+f x))^{2/3}\right )\right )+\frac {3 \sqrt [3]{c+d \tan (e+f x)} \left (9 c^3-37 c d^2-d \left (3 c^2+49 d^2\right ) \tan (e+f x)+2 d^2 \sec ^2(e+f x) (c+7 d \tan (e+f x))\right )}{35 d^3}}{4 f} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 9 vs. order
3.
time = 0.37, size = 131, normalized size = 0.25
method | result | size |
derivativedivides | \(\frac {\frac {3 \left (c +d \tan \left (f x +e \right )\right )^{\frac {10}{3}}}{10}-\frac {6 c \left (c +d \tan \left (f x +e \right )\right )^{\frac {7}{3}}}{7}+\frac {3 c^{2} \left (c +d \tan \left (f x +e \right )\right )^{\frac {4}{3}}}{4}-\frac {3 d^{2} \left (c +d \tan \left (f x +e \right )\right )^{\frac {4}{3}}}{4}+\frac {d^{4} \left (\munderset {\textit {\_R} =\RootOf \left (\textit {\_Z}^{6}-2 c \,\textit {\_Z}^{3}+c^{2}+d^{2}\right )}{\sum }\frac {\textit {\_R}^{3} \ln \left (\left (c +d \tan \left (f x +e \right )\right )^{\frac {1}{3}}-\textit {\_R} \right )}{\textit {\_R}^{5}-\textit {\_R}^{2} c}\right )}{2}}{f \,d^{3}}\) | \(131\) |
default | \(\frac {\frac {3 \left (c +d \tan \left (f x +e \right )\right )^{\frac {10}{3}}}{10}-\frac {6 c \left (c +d \tan \left (f x +e \right )\right )^{\frac {7}{3}}}{7}+\frac {3 c^{2} \left (c +d \tan \left (f x +e \right )\right )^{\frac {4}{3}}}{4}-\frac {3 d^{2} \left (c +d \tan \left (f x +e \right )\right )^{\frac {4}{3}}}{4}+\frac {d^{4} \left (\munderset {\textit {\_R} =\RootOf \left (\textit {\_Z}^{6}-2 c \,\textit {\_Z}^{3}+c^{2}+d^{2}\right )}{\sum }\frac {\textit {\_R}^{3} \ln \left (\left (c +d \tan \left (f x +e \right )\right )^{\frac {1}{3}}-\textit {\_R} \right )}{\textit {\_R}^{5}-\textit {\_R}^{2} c}\right )}{2}}{f \,d^{3}}\) | \(131\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 3638 vs.
\(2 (434) = 868\).
time = 1.20, size = 3638, normalized size = 6.93 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt [3]{c + d \tan {\left (e + f x \right )}} \tan ^{4}{\left (e + f x \right )}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 18.88, size = 1015, normalized size = 1.93 \begin {gather*} \ln \left ({\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}+f\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,1{}\mathrm {i}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}+{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}\,\left (2\,c\,\left (\frac {6\,c^2}{d^3\,f}-\frac {3\,\left (c^2+d^2\right )}{d^3\,f}\right )-\frac {12\,c^3}{d^3\,f}+\frac {6\,c\,\left (c^2+d^2\right )}{d^3\,f}\right )+\left (\frac {3\,c^2}{2\,d^3\,f}-\frac {3\,\left (c^2+d^2\right )}{4\,d^3\,f}\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{4/3}+\ln \left (-c\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}+d\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}\,1{}\mathrm {i}+f^4\,{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{4/3}+2\,d\,f\,{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\right )\,{\left (\frac {-d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}-\ln \left (-\frac {486\,\left (d^8-c^4\,d^4\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f^4}+\frac {{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{2/3}\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {3888\,d^5\,\left (c^2+d^2\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f}-3888\,c\,d^4\,{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (c^2+d^2\right )\right )}{4}+\frac {1944\,c\,d^5\,\left (c^2+d^2\right )}{f^3}\right )}{2}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (\frac {-d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}+\ln \left (\frac {486\,\left (d^8-c^4\,d^4\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f^4}-\frac {{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{2/3}\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {3888\,d^5\,\left (c^2+d^2\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f}+3888\,c\,d^4\,{\left (\frac {-d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (c^2+d^2\right )\right )}{4}-\frac {1944\,c\,d^5\,\left (c^2+d^2\right )}{f^3}\right )}{2}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (\frac {-d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}+\frac {3\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{10/3}}{10\,d^3\,f}-\ln \left (-\frac {486\,\left (d^8-c^4\,d^4\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f^4}+\frac {\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {\left (\frac {3888\,d^5\,\left (c^2+d^2\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f}-3888\,c\,d^4\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (c^2+d^2\right )\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{2/3}}{4}+\frac {1944\,c\,d^5\,\left (c^2+d^2\right )}{f^3}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}}{2}\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}+\ln \left (\frac {486\,\left (d^8-c^4\,d^4\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f^4}-\frac {\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,\left (\frac {\left (\frac {3888\,d^5\,\left (c^2+d^2\right )\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{1/3}}{f}+3888\,c\,d^4\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}\,\left (c^2+d^2\right )\right )\,\left (\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{2/3}}{4}-\frac {1944\,c\,d^5\,\left (c^2+d^2\right )}{f^3}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{f^3}\right )}^{1/3}}{2}\right )\,\left (-\frac {1}{2}+\frac {\sqrt {3}\,1{}\mathrm {i}}{2}\right )\,{\left (-\frac {d+c\,1{}\mathrm {i}}{8\,f^3}\right )}^{1/3}-\frac {6\,c\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{7/3}}{7\,d^3\,f} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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